Tangent line to y = e^(3x + cos x) at x = 0

[shamieh]

find the equation of the tangent line.$$y = e^{3x + cos x}$$ @ x = 0

$$
y1 = e^{3(0) + cos(0)} = e^1 = e$$
$$y1 = e$$

$$y = e^{3x+cos x}$$
$$y' = e^{3x + cos x} * (3 - sinx)$$

$$m = 3e$$

$$
y - e = 3e(x - 0) $$

 

[topsquark]

find the equation of the tangent line.$$y = e^{3x + cos x}$$ @ x = 0

$$
y1 = e^{3(0) + cos(0)} = e^1 = e$$
$$y1 = e$$

$$y = e^{3x+cos x}$$
$$y' = e^{3x + cos x} * (3 - sinx)$$

$$m = 3e$$

$$
y - e = 3e(x - 0) $$

Looks good to me!

-Dan

 

[shamieh]

Thank God! Was so worried about the $$e^1 = e $$