MATLAB Help with Math: Calculate Manually, No MATLAB Needed

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SUMMARY

The discussion focuses on manually calculating the derivative of the implicit function defined by the equation $y^4 + xy = 2x^2 - 7x + 7$. The derivative is derived using implicit differentiation, resulting in $\frac{dy}{dx} = \frac{4x - y - 7}{4y^3 + x}$. At the point (1, 1), the slope of the tangent line is calculated as $\frac{dy}{dx} = \frac{-4}{5}$. Consequently, the equation of the tangent line, denoted as T(x), is determined to be $T(x) = -\frac{4}{5}(x - 1) + 1 = -\frac{4}{5}x + \frac{1}{5}$.

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Students and educators in mathematics, particularly those focusing on calculus and derivative calculations, as well as anyone seeking to improve their manual computation skills without relying on software like MATLAB.

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Can someone help me with this? You don't need to do MATLAB, just compute manually.
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Have you calculated T(x)? You are given $y^4+ xy= 2x^2- 7x+ 7$. Differentiating, $4y^3\frac{dy}{dx}+ y+ x\frac{dy}{dx}= 4x- 7$. $4y^3\frac{dy}{dx}+ x\frac{dy}{dx}= (4y^3+ x)\frac{dy}{dx}= 4x- y- 7$. $\frac{dy}{dx}= \frac{4x- y- 7}{4y^3+ x}$. At (1, 1), $\frac{dy}{dx}= \frac{4- 1- 7}{4+ 1}= \frac{-4}{5}$. $T(x)= -\frac{4}{5}(x- 1)+ 1= -\frac{4}{5}x+ \frac{1}{5}$.
 

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