MHB Tangent to Curve $e^x+k$ at $x=a$: Find $k$

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The function f(x) = e^x + k has a tangent at x = a that passes through the origin. By applying the tangent line equation, the relationship between k and a is established. Setting x = 0 and y = 0 leads to the equation 0 - (e^a + k) = e^a(0 - a). Solving this gives k = e^a(a - 2). Thus, k is expressed in terms of a as k = e^a(a - 2).
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Hi there,

The function $f(x)= e^x+k$ has a tangent to the curve at $x=a$ and going through the origin. Find $k$ in terms of $a$
 
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Bushy said:
The function $f(x)= e^x+k$ has a tangent to the curve at $x=a$ and going through the origin. Find $k$ in terms of $a$
The equation of the tangent line is $y-f(a)=f^{\prime}(a)(x-a)$.
Now let $x=0~\&~y=0$ then solve for $k$.
 
$y-f(a) = f'(a)(x-a)$

and

$0-(e^a+k) = e^a(0-a)$

so

$k=e^a(a-2)$
 
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