Tangent to y axis with center(-3,4) whats the eqn of circle?

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SUMMARY

The equation of a circle with center at (-3, 4) and tangent to the y-axis is derived using the radius, which is the distance from the center to the tangent point on the y-axis. The tangent point is identified as (0, 4), leading to a radius of 3. Consequently, the equation of the circle is expressed as (x + 3)² + (y - 4)² = 9, confirming the correct formulation based on the given parameters.

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the center is (-3,4) and tangent to the y-axis

how will I find the equation of the circle?

I know what tangent means but at what point? Can someone give me a clue? :rolleyes:
 
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I am pretty rusty at this, and I am not sure I understand the wording, but could it simply mean that your circle touches the point (0,4) on the y-axis? I am assuming that the line x = 0 is tangent to the curve.
 
I think the radius is 3

therefore the equation of the circle is

(x+3)^2 + (y-4)^2 = 9

is this correct?
 
that's fine~
 
how come the radius wasnt 4?
 
the center is at (-3, 4) and the circle is tangent to the y axis, which implies that it is tangent at (0, 4). Thus the radius is the distance between (0, 4) and (-3, 4) which is clearly 3.
 

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