Tangential Force in Uniform Circular Motion: Explained

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In uniform circular motion, centripetal acceleration is the inward force that maintains a particle's circular path, while tangential force is not fictitious and can cause angular acceleration. Tangential force is often associated with torque and is not always present in circular motion unless there is a change in speed. A discussion arose regarding a toy car's motion on a circular track, where calculations for both the inward force and tangential force were performed. The tangential force was determined to be 1.68 N, derived from the car's acceleration, while the inward force was calculated to be 0.55 N. Understanding the relationship between these forces is crucial for analyzing circular motion dynamics.
destro47
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In Uniform circular motion, the centripetal acceleration is the inward force that keeps a particle on a circular track. My question is what exactly is the tangential force? Is it a fictious force? My first inclination is that is equal in magnitude to the centripetal force but acts perpendicularly (sort of like the normal force). Is this reasoning correct? Someone please let me know, thanks.
 
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destro47 said:
My question is what exactly is the tangential force? Is it a fictious force? My first inclination is that is equal in magnitude to the centripetal force but acts perpendicularly (sort of like the normal force). Is this reasoning correct? Someone please let me know, thanks.
The tangential force is not a ficticous force; however, just because a particle undergoes circular motion doesn't nesscarily mean that there is a tangential force acting. A tangential force is often referred to as a torque and causes angular acceleration, that is an applied torque increases that angular velocity of the rotating body.

See http://hyperphysics.phy-astr.gsu.edu/HBASE/circ.html#rotcon" for more information on rotation concepts.
 
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Then how does it apply to this problem:

A 7.83 kg toy car is going around a circular track of radius 52.5 m at a constant speed of 17.3 m/s. Find:


- the time it takes for the car to go around the track once

- the magnitude of the inward force needed to keep it moving in a circle

b) The same 7.83 kg toy car now starts at rest on the same track, and accelerates at a constant rate to a final speed of 1.93 m/s in 9.02 seconds. At the instant it reaches its final speed, find:

- the magnitude of the inward force needed to keep it moving in a circle:

- the magnitude of the tangetial force:

Part A was really trivial and I got the answers right on the first try. However, the tangential force thing has thrown me for a bit of loop. For the first answer of part B i think 1.68 N is the answer, but after careful review I think its the answer to question II part B. Is the tangential force a component of the inward force? Does anyone have a clue about this one?
 
My intuition was correct. 1.68 N is the measure of the tangential force, calculated using the acceleration of the car over that particular arc length of the circle. 0.55 N is the measure of the centrifical force keeping the toy car on the circle.
 
tnx....
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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