Tangential speed of moon around earth

Click For Summary

Homework Help Overview

The discussion revolves around calculating the tangential speed of the Moon as it orbits the Earth. The original poster presents a problem from their AP Physics class, providing details such as the mass of the Moon, the time for one revolution, and the distance from the Earth, which is described as the radius of rotation.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply a formula for tangential speed but questions how to express an irrational number like pi in scientific notation. They also seek clarification on the meaning of "radius of rotation" and whether their formula is correct.

Discussion Status

Participants provide guidance on rounding the final answer to a reasonable number of significant figures based on the accuracy of the measurements. There is a clarification that the radius of rotation refers to the distance from the Moon to the Earth's center, and while some participants affirm the formula's correctness, others challenge the notion of the Moon's orbit being a perfect circle.

Contextual Notes

There is an emphasis on significant figures in measurements, noting that the accuracy of the final answer should reflect the least precise measurement among the values used. The discussion also touches on the nature of the Moon's orbit, suggesting it may not be a perfect circle.

rkrk
Messages
4
Reaction score
0
I have this problem for my AP Physics class that discusses the moon circling around the Earth. I am given the mass of the moon, time it takes for one revolution, and the moon's distance from the Earth (the radius of rotation). I am supposed to find out the tangential speed of the Moon traveling around the Earth, and put it into scientific notation. Easy enough, because tangential speed is simply the distance the moon is from the Earth times two times pi divided by the time it takes for one full revolution. However, no matter what the distance is, when ever doing any operation involving pi you will end up with an irrational number. How are you supposed to write a neverending number in scientific notation? Also what exactly does it mean by radius of rotation? Am I doing anything wrong or is my formula for tangential speed incorrent?
 
Physics news on Phys.org
rkrk said:
However, no matter what the distance is, when ever doing any operation involving pi you will end up with an irrational number. How are you supposed to write a neverending number in scientific notation?
While the pure number [itex]\pi[/itex] might be irrational and "neverending" (which is why we represent it by a symbol), your calculation of the speed will not be a pure number. You have to roundoff your final answer to a reasonable number of significant figures. (Based on the accuracy of your values for time and distance.)


Also what exactly does it mean by radius of rotation?
Just what you thought it meant when you produced your formula for tangential speed. The moon travels in a circle around the Earth's center; you are given the radius of that circle, I presume.
Am I doing anything wrong or is my formula for tangential speed incorrent?
Nothing wrong with your formula.
 
Since the distance from the moon to the Earth (radius of rotation) is a measured quantity, it is not exact and is given to some number of "significant figures". G and M are also "measured" and so are given with some number of significant figures. Your answer should have the number of significant figures equal to the smallest of these. (Your calculation can't be more accurate than the least accurate measurement.)
 
Tangential speed is also known as linear velocity. It is tangential speed because the velocity component is tangential to the acceleration component, which is towards Earth. The answer is simple: You know the period and radius of rotation, velocity is simply 2(PI)radius / period.
 
Doc Al said:
The moon travels in a circle around the Earth's center; you are given the radius of that circle, I presume.

Nothing wrong with your formula.
The moon does not travel in a circle around the Earth's center.
 
MeJennifer said:
The moon does not travel in a circle around the Earth's center.
True, but close enough for this problem. :wink:
 

Similar threads

Replies
18
Views
3K
Replies
1
Views
2K
Replies
5
Views
2K
  • · Replies 21 ·
Replies
21
Views
2K
Replies
12
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 14 ·
Replies
14
Views
3K