- #1

Bashyboy

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In this problem, we are assuming circular orbits. Let [itex]v_{es} = r_{es} \omega_{es}[/itex] be the tangential speed of the Earth relative to the sun, the distance between the sun and Earth (which would be 1, as we are working in astronomical units), and the rate at which the Earth rotates around the earth, respectively.

Let [itex]v_{me} = r_{me} \omega_{me}[/itex] be the tangential speed relative to the earth, the distance between Earth and moon, and the rate at which the moon rotates around the earth, respectively.

To find the tangential velocity of the moon with respect to the sun, would I simply compute the quantity [itex]v_{ms} = v_{es} + v_{me} \implies v_{ms} = r_{es} \omega_{es} + r_{me} \omega_{me} [/itex]?