Tarzan swinging on a vine with Jane releasing mid-swing

[Port]

i kinda also need help on another problem. i can't even start this problem because i have no idea how! can someone please tell me how?

Tarzan and Jane, whose total mass is 130kg, start their swing on a 5m long vine when the vine is at an angle of 30 degrees with the horizontal. At the bottom of the arc, Jane, whose mass is 50kg, releases the vine . What is the max height at which Tarzan can land on a branch after his swing continues?

 

[dextercioby]

Consider the application of total mechanical energy conservation law,taking into account the data offered by the problem and a correct drawing which would reflect the unknowns.
HINT:U have to apply this law twice.
Daniel.

 

[Port]

ok i got up to this part and i am stuck:
KEi+PEi=KEf+PEf
0J+mgh=1/2mv^2+0J
h=5cos30
h=4.3m
v=6.5m/s
so now what do i do? where do i do this for next and how do i apply it to MEi=MEf? i am very confused!?

 

[dextercioby]

ok i got up to this part and i am stuck:
KEi+PEi=KEf+PEf
0J+mgh=1/2mv^2+0J
h=5cos30
h=4.3m
v=6.5m/s
so now what do i do? where do i do this for next and how do i apply it to MEi=MEf? i am very confused!?

Did u forget the previous problem??The setup is basically the same,it's just that in this case,the masses vary.So your "h" is again a DIFFERENCE.

Daniel.

 

[Port]

but if i use the same formula with the different masses they cancel out anyway don't they??

 

[dextercioby]

Not for the second case,when Tarzan is left all by himself.The mass in one side of the eq.is Tarzan's mass,while on the other side,it's the mass of the 2 "swingers"...

Daniel.

 

[Yapper]

You posted this already... did you look at my response?