Tarzan swings down to save Jane

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SUMMARY

The discussion focuses on calculating the time it takes for Tarzan to swing down and rescue Jane using principles of kinematics and simple harmonic motion (SHM). Tarzan's mass is 98.3552 kg, and he swings from a height of 4.45 m using a 30.1 m vine. The calculated speed at the bottom of the swing is 9.339 m/s, and the height on the opposite side is 1.7714 m. The solution involves applying energy conservation and harmonic motion concepts to determine the time of the swing.

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  • Understanding of kinematics and motion equations
  • Knowledge of simple harmonic motion (SHM) principles
  • Familiarity with energy conservation in physics
  • Ability to perform calculations involving mass and velocity
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  • Study the equations of motion for simple harmonic oscillators
  • Learn about energy conservation principles in mechanical systems
  • Explore the relationship between angular frequency and amplitude in SHM
  • Practice solving problems involving pendulum motion and swings
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Students studying physics, particularly those focusing on mechanics and motion, as well as educators looking for practical examples of kinematics and harmonic motion applications.

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Homework Statement



Tarzan (mass 98.3552) stands on a 4.45 m cliff next to a river. He grabs a vine of length 30.1 m whose point of support is directly above Jane (mass 57.5336). He grabs Jane at the bottom of his swing and has just enough speed to make it to the other side. How long does the rescue take?

Homework Equations



I assume some kinematics.

The Attempt at a Solution



I already solved the other two parts (Tarzans speed at bottom (9.339 m/s)and height of other side (1.7714 m). I triedd d = .5at^2 for both sides of the swing (down and back up) but didn't expect it to be right. It probably has something to do with harmonic motion?
 
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I can see simple harmonic motion working here. divide it into two parts with separate values for omega (in the SHM, not omega of the rope). Not too hard to do for the first part because you know the final speed. set that equal to (omega)(amplitude) where amp is the max angle. For the second part, do it the same way, but first calculate the initial speed by using energy conservation. Can you go from there?
 
on second thought, I guess you already know that initial speed because you used momentum to find the height of the other side. That makes it easier.
 

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