captainjack2000 Messages 96 Reaction score 0 Thread starter Apr 15, 2009 #1 Homework Statement Could someone please explain how the taylor expansion of 1/(r-r') turns into ( 1/r+(r'.r)/r^3 + (3(r.r')^2-r^2r'^2)/2r^5 +...) Homework Equations The Attempt at a Solution
Homework Statement Could someone please explain how the taylor expansion of 1/(r-r') turns into ( 1/r+(r'.r)/r^3 + (3(r.r')^2-r^2r'^2)/2r^5 +...) Homework Equations The Attempt at a Solution
latentcorpse Messages 1,411 Reaction score 0 Apr 15, 2009 #2 i think it should be [itex]\frac{1}{|\vec{r}-\vec{r'}|}[/itex] yes? use the 3d taylor expansion formula [itex]\phi(\vec{r}+\vec{a})=\sum_{n=0}^{\infty} \frac{1}{n!} (\vec{a} \cdot \nabla)^n \phi(\vec{r})[/itex] with [itex]\phi(\vec{r}+\vec{a})=\frac{1}{|\vec{r}-\vec{r'}|}[/itex]
i think it should be [itex]\frac{1}{|\vec{r}-\vec{r'}|}[/itex] yes? use the 3d taylor expansion formula [itex]\phi(\vec{r}+\vec{a})=\sum_{n=0}^{\infty} \frac{1}{n!} (\vec{a} \cdot \nabla)^n \phi(\vec{r})[/itex] with [itex]\phi(\vec{r}+\vec{a})=\frac{1}{|\vec{r}-\vec{r'}|}[/itex]