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Taylor mechanics chap3,problem 4

  1. Oct 8, 2016 #1
    1. The problem statement, all variables and given/known data
    two man,each of equal mass m,are standing at one end of a stationary railroad flatcar with frictionless wheel and mass mcar.Find the car's speed if the two men run to the other end of the car and jump off simultaneously with the same speed u(relative to the car)
    2. Relevant equations


    3. The attempt at a solution
    let vh be the men's speed relative to the ground at the instant they jump off the car.Thus
    u= vh+vcar.Since the momentum of the system is conservative,2mvh=mcarvcar

    After solving the equations,i got (2mu)/(2m+mcar) ,but i found a different answer from mine on the website http://chriskranenberg.wix.com/taylor-mechanics-solutions.I want to make sure which one is right
     
    Last edited: Oct 8, 2016
  2. jcsd
  3. Oct 8, 2016 #2

    gneill

    User Avatar

    Staff: Mentor

    Your notation is strange. What is, for example, [m][/h] meant to convey?

    You'll need to show the details of your own solution, how you arrived at your result. Helpers won't just confirm or deny a given solution for you.
     
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