Taylor polynomial, approximative solution of this equation

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SUMMARY

The discussion focuses on finding an approximate solution to the equation 4x = (1/3)*cos(3x) within the interval [0,1] using a Taylor polynomial of degree 2 centered at 0. The Taylor polynomial derived is (1/3) - (3x^2)/2. Participants emphasize the need to solve the resulting second-order polynomial by applying the quadratic formula to find the values of x that yield zero.

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Homework Statement


The equation 4x = (1/3)*cos(3x) has a solution on the interval [0,1]. Find an approximative solution by replacing the right hand side with a Taylor polynomial of degree 2 around 0.

Homework Equations

The Attempt at a Solution


So as I understand the task we should find a Taylor polynomial of (1/3)*cos(3x) around 0. I have found this to be
(1/3)-(3x^2)/2. However, which value of x should I put into the equation in order to estimate the solution? I know it must be in the interval [0,1], but unsure of the value.
 
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Subtract the 4x from both sides and then you are looking for the zeros of a second order polynomial. Use the quadratic equation to find the values of x that give zero.
 
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Excellent, thank you!
 
Kqwert said:

Homework Statement


The equation 4x = (1/3)*cos(3x) has a solution on the interval [0,1]. Find an approximative solution by replacing the right hand side with a Taylor polynomial of degree 2 around 0.

Homework Equations

The Attempt at a Solution


So as I understand the task we should find a Taylor polynomial of (1/3)*cos(3x) around 0. I have found this to be
(1/3)-(3x^2)/2. However, which value of x should I put into the equation in order to estimate the solution? I know it must be in the interval [0,1], but unsure of the value.

You have an equation of the form ##x = f(x)## (where ##f(x) = (1/12) \cos(3x)##), and you replace it by a simpler approximate equation ##x = g(x),##, where ##g(x)## is an approximation to ##f(x).## Just go ahead and solve the simpler, approximate equation.
 

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