Taylor Polynomial of f(x) = x^3sin(x)

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SUMMARY

The discussion focuses on finding the first three non-zero terms of the Taylor polynomial for the function f(x) = x^3 sin(x) at a = 0. The correct approach involves using the Maclaurin series for sin(x) and multiplying it by x^3. The user initially provided an incorrect answer by summing factorial terms without deriving the polynomial correctly. The key takeaway is the importance of understanding the Taylor series expansion and applying it accurately to obtain the polynomial terms.

PREREQUISITES
  • Understanding of Taylor series and Maclaurin series
  • Knowledge of derivatives and their computation
  • Familiarity with the function sin(x) and its Taylor series expansion
  • Basic algebraic manipulation of polynomial expressions
NEXT STEPS
  • Study the Taylor series expansion for sin(x) in detail
  • Practice deriving Taylor polynomials for various functions
  • Learn about the product rule for differentiation
  • Explore examples of Maclaurin series in calculus textbooks
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Students studying calculus, particularly those focusing on Taylor series and polynomial approximations, as well as educators seeking to clarify concepts related to series expansions.

november1992
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Homework Statement



Find the first 3 non-zero terms of the Taylor polynomial generated by f (x) = x^{3} sin(x) at a = 0.

Homework Equations


f^{n}(x) * (x-a)^{n} / (n!)

The Attempt at a Solution



I got the question wrong: my answer was 1/3! + 1/5! + 1/7!
Here is the answer below. I was wondering how my teacher got that answer. Do you have to do the product rule to find the derivatives?
sxjbfc.png
 
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Do you know the Taylor series for ##\sin x\ ##? He just multiplied that by ##x^3##.
 
november1992 said:

Homework Statement



Find the first 3 non-zero terms of the Taylor polynomial generated by f (x) = x^{3} sin(x) at a = 0.

Homework Equations


f^{n}(x) * (x-a)^{n} / (n!)

The Attempt at a Solution



I got the question wrong: my answer was 1/3! + 1/5! + 1/7!
Here is the answer below. I was wondering how my teacher got that answer. Do you have to do the product rule to find the derivatives?
sxjbfc.png

The Taylor polynomial is a function of x. Your answer is really just a single number.

You wrote something in the relevant equation section. Do you know what it represents and what it's used for?

Your textbook undoubtedly has some examples that are like this problem. Have you looked at any of them?
 
At a=0, it means that the function f(x) is approximated near the point x=a=0. In other words, you have a Maclaurin series. Adapt and use the relevant equation from your post #1.
 

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