1. The problem statement, all variables and given/known data A Pyrex container is filled to the very top with 40.0L of water. Both the container and the water are at a temperature of 90.0 degrees C. When the temperature has cooled to 20.0 degrees C how much additional water can be added to the container? 2. Relevant equations (delta-V)/(V-initial)=(beta)(delta-T) (delta-L)/(L-initial)=(alpha)(delta-T) (delta-A)/(A-initial)=2(alpha)(delta-T) 3. The attempt at a solution The change in the volume of water: (delta-V)=(beta-water)(delta-T)(V-initial)=(207*10^-6/K)(70K)(40L)=0.5796L the final volume of water- 39.4204 L change in holding capacity of Pyrex container: I used the equation for change in linear direction for the height of the cylinder and change in the area for the cross-sectional area of the cylinder. (delta-L)=(alpha-Pyrex)(delta-T)(L-initial)=(3.25*10^6/K)(70K)(L-intial) final length=.9997725(L-initial) (delta-A)=2(alpha)(delta-T)(A-initial)=2(3.25*10^6/K)(70K)(A-initial) final area=.999545(A-initial) final volume of cylinder=final length*final area=.9993176(V-initial)=.9993176(40L)=39.9727 L final volume of cyliner-final volume of water=0.5523L Does my method make sense?