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Tension and fundamental frequency

  1. Nov 23, 2009 #1
    1. The problem statement, all variables and given/known data

    A particular violin string plays at a fundamental frequency of 294Hz. If the tension is increased 15%, what will be the new fundamental frequency?

    2. Relevant equations

    f=v/2L
    v=sqrt(T/(m/L))

    3. The attempt at a solution

    294 = sqrt(T/(m/L))/2L so T=(294*2L)^2/(m/L)

    T2 = T1*1.15

    T2 = 1.15 * (((588L)^2)/(m/L))

    I could go on and plug this into f2 = sqrt(T2/(m/L)) but it's a lot of typing and it didn't get me anywhere.

    I'm not sure if I'm maybe making this problem more difficult than it has to be but I'm at a loss as to what to do. Any help would be greatly appreciated.



    ***second attempt at this problem

    u=m/L

    v = sqrt(1.15T/u)

    sqrt(T/u)=v/sqrt(1.15)

    f= v/(sqrt(1.15)*2L)

    294*sqrt(1.15) = 315.28Hz

    No idea if this is right, but it's all I could come up with.
     
    Last edited: Nov 23, 2009
  2. jcsd
  3. Nov 23, 2009 #2

    rl.bhat

    User Avatar
    Homework Helper

    Hi raindrops, welcome to PF.
    Your second attempt is correct.
     
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