Is Tension Constant in a Massless String?

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SUMMARY

Tension in a massless string remains constant throughout its length due to the absence of mass. When analyzing a segment of the string with mass Δm, the forces acting on it are T1 to the right and T2 to the left. The force equation T2 - T1 = Δma indicates that since Δm equals zero, T2 must equal T1. This confirms that tension is uniform across the entire length of the massless string.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Basic knowledge of force equations
  • Familiarity with concepts of mass and acceleration
  • Comprehension of tension in physics
NEXT STEPS
  • Study the implications of massless objects in physics
  • Explore tension in non-massless strings and its variations
  • Learn about the role of acceleration in force equations
  • Investigate real-world applications of tension in engineering
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Physics students, educators, and anyone interested in understanding the principles of tension and force in mechanics.

andyrk
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Why is tension in a massless string same throughout its length?
 
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andyrk said:
Why is tension in a massless string same throughout its length?

Consider a massless string being pulled horizontally towards right.

The forces acting on a tiny bit of the string having mass Δm will be T1 towards right and T2 towards left.The force equation will be T2-T1=Δma where 'a' is the acceleration of the tiny bit of the string .Now since Δm=0 ∴ T2=T1 i.e tension on either side of any arbitrary mass of the string is zero.In other words tension throughout the string is constant.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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