- #1
phantomvommand
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- Homework Statement
- See picture below
- Relevant Equations
- F = kx
Resolving forces?
Is this even solvable? I don't know where to begin.
Tension in a spring that's bent into a semicircle
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SUMMARY
The discussion centers on the analysis of tension in a spring bent into a semicircular shape, specifically addressing the forces acting on the spring and the resulting tension in the attached string. Key equations referenced include F = kx, where F is the force, k is the spring constant, and x is the displacement. Participants emphasize that the spring's behavior under bending involves shear moments and internal tension, which must be balanced for the system to remain in equilibrium. The conversation concludes with a focus on understanding the moments and tensions involved in maintaining the spring's shape.
PREREQUISITES- Understanding of Hooke's Law (F = kx)
- Familiarity with shear moments and torsion in materials
- Basic knowledge of equilibrium conditions in mechanics
- Concept of bending moments in structural analysis
- Study the mechanics of springs, focusing on helical spring behavior under tension and compression.
- Learn about bending moments and their effects on structural integrity in materials.
- Explore the concept of equilibrium in mechanical systems, particularly in relation to forces and moments.
- Investigate the relationship between tension and internal forces in curved structures.
Students of physics and engineering, particularly those studying mechanics and materials science, as well as professionals involved in structural analysis and design.
Is this even solvable? I don't know where to begin.
- #2
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Judging from the diagram, the spring starts compact, i.e. it cannot be compressed (much).phantomvommand said:
Consider the outermost parts of the spring in the curved position. What length is that now?
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- #3
phantomvommand
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Are you suggesting that the diameter of the semicircle is (D + 2L/pi)?haruspex said:
I think I need help with understanding how a vertical tension in the string even arises. It is obvious intuitively, but when I break the spring down into an infinitesimal element I cannot figure out why.
Considering the small element of the spring where the string is attached to, it experiences a leftward spring / tension force, and a downward tension force from the string. Yet, it is in equilibrium. Presumably, the leftward tension is balanced by some rightward friction with the string? But how about the downward tension force? What gives rise to a necessary upward force which the downward string tension must balance?
If my method of analysis above is incorrect, I'd be happy to hear how else the tension in the string arises.
- #4
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Yes, it is non obvious.phantomvommand said:
When a helical spring is stretched, each small cylindrical element of the wire is twisted about its axis. So it involves shear moments, like a torsion wire. (Confusingly, a "torsion spring" works through bending moments.)
However, you are probably not expected to get into such detail.
Nearly right… think that through again.phantomvommand said:
But it is not the diameter that is of direct relevance; as I asked, what is the distance around the outer perimeter of the curved spring? Hence, how much has the spring been stretched on that side?
- #5
Lnewqban
Homework Helper
Gold Member
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The thing is, as the picture shows, that bent spring will not take the shape of a semicircle.phantomvommand said:
The apex is under a greater amount of bending moment than the cross-sections closer to the ends.
What is the subject to which this problem is related?
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True, but the question explicitly states it is to be taken to be a semicircle.Lnewqban said:
- #7
phantomvommand
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If I am understanding correctly, you are suggesting that assuming the spring is not stretched much, it's inner circumference is L, which gives an outer perimeter length of (L + D*pi).haruspex said:
Are you suggesting that the tension is then kD*pi?
I am a little confused as to how such a tension translates into a net vertical tension required at the ends with the string, and furthermore, why is this tension, which is calculated only for the outer perimeter of the spring, representative of the overall tension at all points in the spring?
- #8
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Not quite. As you note, that is only for the most stretched arc through the spring. What would it be on average? Bear in mind the circular nature of each coil of the spring.phantomvommand said:
The next step would be to consider moments.phantomvommand said:
Having found the effective tension in the spring, think of the spring as two rigid quadrants hinged by a single coil of the spring. Take the balance of moments about the innermost point of that coil.
- #9
Lnewqban
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A spring does not behave like a rubber band.phantomvommand said:
Besides accepting stretching, it can be compressed (if pitch of coils allows space for it), and can also be bent, or even twisted.
Our spring has been bent until reaching the shown shape.
As I can see spaces between the coils still in the bent position, I would assume that there is a neutral axis, a compressed concave side and a stretched convex side (just like it happens to a beam subjected to bending loads).
Please, see:
https://en.wikipedia.org/wiki/Bending
If that is true, at each end of the spring, a moment had to be applied, in order to achieve a semi-circular shape.
The magnitude of that moment should be equal to stretching force times D, or compressing force times D, or (stretching force + compressing force) times D/2.
If you now attach the string to both ends, and remove the bending moments applied to the ends, the spring can’t keep the semicircular shape, but a tension appears in the string.
There is now an internal moment that grows in magnitude from each end to the apex, where is value is maximum.
The tension of your string is now perfectly balancing all those internal moments, since the spring is in repose.
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As I wrote in post #2, it doesn’t look that way to me (except near the ends, where the moment from the string is weak).Lnewqban said:
A moment had to be applied whether or not the coils are touching their neighbours on the inside of the curve.Lnewqban said:
Lnewqban said:
I don't understand those last two points. The sequence you described seems to beLnewqban said:
- manually bending the spring into the arc
- attaching the string
- releasing the spring so that the string is in tension
- #11
Lnewqban
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My post was directed to the OP, who stated he needs help understanding the reason for the string tension (please, see selected header quote in my last post).haruspex said:
As you may know by now, sometimes I induce confusion as I try to explain my ideas, as English is not my native language.
My apologies, @haruspex