Tension in rope between blocks on an incline

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SUMMARY

The discussion focuses on calculating the tension in a rope connecting two blocks sliding down an inclined plane. The blocks, with masses mA and mB and coefficients of friction μA and μB, experience different frictional forces due to μA being less than μB. The correct approach involves using free body diagrams to analyze the forces acting on each block, leading to the conclusion that the tension can be expressed in terms of the masses and the angle of inclination θ. The user successfully derived the tension after clarifying the forces involved.

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  • Understanding of Newton's Second Law of Motion
  • Knowledge of free body diagrams
  • Familiarity with friction coefficients
  • Basic concepts of inclined planes in physics
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  • Study the derivation of tension in systems with multiple masses
  • Learn about the effects of different friction coefficients on motion
  • Explore advanced applications of Newton's laws in multi-body systems
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Students studying physics, particularly those focusing on mechanics, as well as educators and anyone interested in understanding the dynamics of systems involving tension and friction on inclined planes.

Alvin92SD
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1. Two blocks made of different materials connected together by a thin rope, slide down a plane ramp inclined at an angle θ to the horizontal (block B is above block A). The masses of the blocks are mA and mB, and the coefficients of friction are μA and μB. If μA < μB, find the tension in terms of mA, mB, and θ



2. The first part of the question is to find the accelearation, a, which I've done and got the correct answer. Finding the tension is the second part of the question, which I've no idea at all how to do. Also, I'm not sure I really understand what tension is.



3. I've tried T=Fa-Fb ,but I didn't get the answer.
 
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Did you draw a free body diagram? There are three forces acting on each block, two of which you know (if you got the acceleration right). You know that the sum of the forces in the direction of motion is equal to m*a. You have a component of the weight force in the direction of motion, you have the friction force, and you have the unknown tension. The mass should cancel out.
 
Thank you, I've got the right answer now.
 

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