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Tension in the chain from a distance

  1. Dec 10, 2014 #1
    1. The problem statement, all variables and given/known data
    A chain of mass ##M## and length ##L## held vertically by fixing its upper end to a rigid support. The tension in the chain at a distance ##y## from the rigid support is

    2. Relevant equations
    ##F=ma## (Newton's 2nd law)

    3. The attempt at a solution
    Since net acceleration, ##a=0##,
    Therefore, ##F=0##
    Hence, ##T=Mg##,
    Then onward I don't seem to get my head around.
    The answer given is :
    ##\frac{Mg(L-y)}{L}##
     
  2. jcsd
  3. Dec 10, 2014 #2

    BvU

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    How about considering a point half way ? Is the full weight hanging from that point ?
     
  4. Dec 10, 2014 #3
    I think the approach can be implemented in the problem.
     
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