Tension of cables of unequal length

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SUMMARY

The discussion centers on the tension in cables of unequal length supporting a uniformly dense mass. It concludes that the tensions T1 and T2 are not equal due to the differing lengths of the cables. To calculate the tensions, one must apply the principle of moments, ensuring that the sum of moments about any point equals zero, which prevents the mass from rotating around its center of mass.

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mikejones222
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While doing some "what is the tension in cable" of hanging masses problems, I thought of the following scenario: a mass, uniform in density, is suspended by two cables of unequal length (See attachment)

Assuming that the mass is uniform in density, would T1 be the same as T2? Intuitively, it seems as though T1 may be less, but wasn't sure. If it's not, then how would one go about calculating the tension?
 

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  • mass hanging slanted.png
    mass hanging slanted.png
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Hi mikejones222! http://img96.imageshack.us/img96/5725/red5e5etimes5e5e45e5e25.gif

You draw the 3 forces: what you've shown together with weight acting down through the centre of mass. Sum of moments about any convenient point = 0. :wink:
 
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riiiight...if tensions were unequal, then the mass would rotate around it's center of mass...thanks:)
 

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