A 65.0 kg tightrope walker stands at the center of a rope. The rope supports are 10 m apart and the rope sags 10.0^\circ at each end. The tightrope walker crouches down, then leaps straight up with an acceleration of 7.70 {\rm m}/{\rm s}^{2} to catch a passing trapeze. What is the tension in the rope as he jumps?(adsbygoogle = window.adsbygoogle || []).push({});

F=ma

Forces, basically.

So, based on the information, I think it's correct to assume because of the tightwalker jumping upwards then the Force from the tightwalker is slackened to 9.8(gravity) - 7.70(acceleration upwards).

From there: F=F_{y}sin([tex]\theta[/tex])+F_{y}sin([tex]\theta[/tex]) - ma (from the tightwalker) = 0

I plug it in and get 180.71 and it's not the correct answer. I'm doing something wrong here.

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# Homework Help: Tension on a rope from jumping tightwalker

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