A 65.0 kg tightrope walker stands at the center of a rope. The rope supports are 10 m apart and the rope sags 10.0^\circ at each end. The tightrope walker crouches down, then leaps straight up with an acceleration of 7.70 {\rm m}/{\rm s}^{2} to catch a passing trapeze. What is the tension in the rope as he jumps?(adsbygoogle = window.adsbygoogle || []).push({});

F=ma

Forces, basically.

So, based on the information, I think it's correct to assume because of the tightwalker jumping upwards then the Force from the tightwalker is slackened to 9.8(gravity) - 7.70(acceleration upwards).

From there: F=F_{y}sin([tex]\theta[/tex])+F_{y}sin([tex]\theta[/tex]) - ma (from the tightwalker) = 0

I plug it in and get 180.71 and it's not the correct answer. I'm doing something wrong here.

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Tension on a rope from jumping tightwalker

**Physics Forums | Science Articles, Homework Help, Discussion**