If you need to find the tensions in the cables T1 and T2 I would do as follows:
Sum of the forces along the x-axis and y-axis must be zero, because the net force on the hanging mass is zero. For the x- component of forces,
-T1 cos theta1 + T2 cos theta 2 = 0
( x component of T1 is on the negative x - axis )
Plug in theta 1 and theta 2 from the problem:
Solve for one tension in terms of the other you would get some thing like this :
T2 = some number * T1 or vice versa.
And for y - component of the forces :
T1 sin theta1 + T2 sin theta2 - W = 0. Here -W since since weight is suspended in the y direction.
Solve this equation too, and subsitute one tension in terms of the other from the first equation.
You can get the two tensions.
Hope this helps!, if I have understood the problem correctly.