Pulley Problem / Coupled Motion Question

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Homework Help Overview

The discussion revolves around a standard pulley problem involving two masses, one on a frictionless table and the other hanging off the edge. The original poster is questioning the reasoning behind the tension in the string when one mass is held at rest.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to analyze the forces acting on the system, questioning why their logic leads to an unexpected conclusion regarding the tension in the string. Some participants highlight the importance of considering the force exerted by a hand holding the mass on the table.

Discussion Status

The discussion is exploring the roles of various forces in the system, particularly the tension in the string and the force applied by the hand. Participants are clarifying assumptions about net forces and the conditions for equilibrium without reaching a definitive conclusion.

Contextual Notes

Participants are considering the implications of a frictionless surface and the conditions under which the system is at rest, while also addressing the balance of forces in both the x and y dimensions.

johnsonandrew
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I have a question about a question; I know how to solve it, but I want to know why I can't do something to get the answer:


Problem is:

Standard pulley problem setup. A mass, M, equaling 2.00 kg is on top of a table with a frictionless surface. A second mass, m, equaling 10.0 kg, is attached to it by a string and hanging off the table by a pulley. What will the tension in the string be if someone holds M at rest?

Attempt:

M= 2 kg
m= 10 kg
Ffriction= 0
Ftension= ?

Fxtotal= 0
Fytotal=0

Fxtotal= Ft - Ff
why does 0 = Ft - 0 not work ?


I know that would mean Ft would have to equal zero, and I know that's not the answer. Why is Fxtotal not zero? Or is the problem something else...

Sum of Forces, x, = m*a, and acceleration is zero because the system is not moving, right? What's wrong with this logic...
 
Last edited:
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You are leaving out the force of the hand holding block M.

Net force is zero, in both x and y dimensions. There is no friction. The tension at one end of the string must balance the weight of the hanging mass. The tension at the other end of the string must the be balanced by the hand.
 
Chi Meson said:
You are leaving out the force of the hand holding block M.

Net force is zero, in both x and y dimensions. There is no friction. The tension at one end of the string must balance the weight of the hanging mass. The tension at the other end of the string must the be balanced by the hand.

Ohh yeahhhh. I knew it didn't make sense. Thanks a lot for clearing that up
 
As m is at rest, the net force on it is zero. Hence, tension in the string = mg.
 

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