Tension Required for 1200-kg Car @ 0.60m/s2

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SUMMARY

The tension required for a rope to accelerate a 1200-kg car at an acceleration of 0.60 m/s² is calculated using Newton's second law, F = ma. By applying this formula, the force (tension) can be determined as 720 N. This calculation assumes that friction is negligible, allowing for a straightforward application of the formula without additional forces acting on the system.

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  • Understanding of Newton's second law of motion
  • Basic knowledge of force and mass calculations
  • Familiarity with units of measurement (Newton, kg, m/s²)
  • Concept of frictionless motion in physics
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  • Study the implications of friction on tension calculations
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Homework Statement


How much tension must a rope withstand if it is used to accelerate a 1200-kg car at 0.60m/s2? Ignore friction


Homework Equations





The Attempt at a Solution

 
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Welcome to PF!

annala said:
How much tension must a rope withstand if it is used to accelerate a 1200-kg car at 0.60m/s2?

Hi annala! Welcome to PF! :smile:

Use good ol' Newton's second law … F = ma. :wink:
 

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