Tensor Operators: Find an Accessible Textbook & Explanations

[Jolb]

I'm taking a course that's taught out of Shankar, and I'm going to be tested on Tensor Operators, which is 15.3, p.417-421 in Shankar. I've never actually worked with tensors before (except the Maxwell stress tensor in EM), and I find that section too hard to understand.

Does anyone know of a more accessible treatment of tensor operators in another textbook? Particularly one that covers basics about tensors instead of assuming some prior exposure. (Tensor operators are way beyond my go-to book, Griffiths.) Here is an example of a problem I'm supposed to be able to do but I'm absolutely lost:

Construct a spherical tensor operator of rank 2 from the components of the Cartesian tensor operator T_jk=x_jx_k.

I would really appreciate any suggestions, or even explanations if you feel generous enough to explain tensor operators.

 

[atyy]

Scalar: 0 indices
Vector: 1 index
Matrix: 2 indices
Tensors: N indices

http://galileo.phys.virginia.edu/classes/752.mf1i.spring03/TensorOperators.htm
http://hexagon.physics.wisc.edu/teaching/2008s_ph449/angular%20momentum%20v.6.PDF

 

[Jim Kata]

Sakurai explains how to do this, and you can get by with Griffith's quantum mechanics book to do this. In Sakurai they work your specific example of a dyad. To get some idea how this works all you need to know is how to expand the tensor product of two vectors in terms of a direct sum. That is formula 4.186 in Griffifths quantum mechanics book |j_1,m_1>\otimes|j_2,m_2>=\sum <j_1 j_2 ; m_1 m_2|j_1 j _2 ; j m>|j,m>

So we have something like U_iV_j|1,i>\otimes|1,j>

We know by the triangle rule of adding angular momentum that where going to get a 2, 1, and 0. That is a rank 2 tensor a vector and a scalar. This just means that the tensor product of two vectors breaks down into the direct sum of a scalar, vector, and a rank 2 tensor. Let's see how this works explicitly. Consider, U_1V_-1|1,1>\otimes|1,-1> Using the Clebsch Gordon formula we get that U_1V_-1|1,1>\otimes|1,-1>=U_1V_-1(1/\sqrt{6}|2,0>+1/\sqrt{2}|1,0>+1/\sqrt{3}|0,0>) Working through all the combos of U and V you can see what goes where and you can check your answer in Sakurai page 236