Terminal Velocity In Glycerin 2.10 in "Classical Mechanics" 1. The problem statement, all variables and given/known data For a steel ball bearing (diameter 2mm and density 7.8g/cm3) dropped in glycerin (density 1.3g/cm3 and viscosity 12 N s/m2 at STP) the dominant drag force is linear drag given by flin = 3*pi*n*D*v where D is the sphere's diameter, v is velocity, n is the viscosity of the fluid a) Find the Characteristic time and terminal speed vter. Include Archimedes buoyant force as a 3rd force. b) How long after it is dropped from rest will the ball bearing have reached 95% of its terminal velocity c) Use flin = 3*pi*n*D*v and fquad=kpAv2 (p being density) with k = 1/4 and compute fquad/flin at the terminal speed 2. Relevant equations v(t) where t = characteristic time = 0.63vter vter = g*t 0.95vter = 3t where t = characteristic time Fbouyancy = (pi/6)d3p*g (p being density of fluid) 3. The attempt at a solution So far I've gotten for part a) (3.2672x10-8 kg)*9.8m/s = 3.202E-7 N (for gravitational force) 3*pi*n*D*v = 3.202E-7N - (pi/6)d3p*g Is this correct? Solve for v above and that's terminal velocity? if so I'm good for the rest of the problem.