Tertiary Alcohols: Can't be Oxidized & Breaking C-C Bonds

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Discussion Overview

The discussion centers on the oxidation of tertiary alcohols, specifically addressing why they cannot be oxidized and the implications of breaking carbon-carbon (C-C) bonds in the process. Participants explore theoretical aspects of organic chemistry related to oxidation reactions and molecular structure.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • Some participants assert that tertiary alcohols cannot be oxidized because the carbon atom bearing the hydroxyl (-OH) group lacks hydrogen atoms.
  • One participant questions whether the oxygen could take a hydrogen from the -OH group and another from a neighboring carbon atom, suggesting a potential pathway for oxidation.
  • Another participant explains that no carbonyl product can be formed from this process, reinforcing the idea that tertiary alcohols are not oxidizable due to the structure of the -OH group.
  • A suggestion is made that using fluorine gas could oxidize tertiary alcohols by breaking the entire molecule, indicating an alternative but extreme method of oxidation.
  • Participants discuss the energy considerations involved in removing hydrogen from non-adjacent carbon atoms, noting that this would require additional energy due to charge transfer effects.
  • There is a mention that converting the -OH group to a double bond would necessitate breaking a C-C bond, as carbon cannot exceed four bonds.

Areas of Agreement / Disagreement

Participants express differing views on the oxidation of tertiary alcohols, with some agreeing on the inability to oxidize them under normal conditions, while others propose alternative methods. The discussion remains unresolved regarding the feasibility of oxidation pathways and the implications of breaking C-C bonds.

Contextual Notes

Participants highlight limitations related to the structural constraints of tertiary alcohols and the energy requirements for potential oxidation reactions. There are unresolved questions about the mechanisms involved in breaking C-C bonds during oxidation.

GeneralOJB
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I've learned that tertiary alcohols can't be oxidised because the carbon bearing the OH contains no hydrogen atoms. But why can't the oxygen just take the hydrogen from the OH and another hydrogen from another carbon atom on the molecule?

I also read that it would involve breaking a C-C bond - how so?
 
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Alcohols are oxidized to carbonyls (as in organic chemistry). And what are you saying, involving H from Alcohol and H from neighboring C-atom, no carbonyl product can be formed, hence tertiary alcohols are not oxidizable due to the virtue of -OH group being there.

But if you are hell bent to oxidize it, just take fluorine gas, it will break the entire molecule and oxidize it.
 
GeneralOJB said:
I've learned that tertiary alcohols can't be oxidised because the carbon bearing the OH contains no hydrogen atoms. But why can't the oxygen just take the hydrogen from the OH and another hydrogen from another carbon atom on the molecule?

I also read that it would involve breaking a C-C bond - how so?

If you took the hydrogen from the oxygen and another hydrogen from a non-adjacent carbon atom, you would then need to connect the oxygen to something and the carbon to something. Also, taking a hydrogen from non-adjacent carbon takes more energy since the oxygen (without a hydrogen) transfers some of it charge to the adjacent carbon, which makes the adjacent hydrogen easier to remove.

Since there are only C-C bonds on a tertiary alcohol (aside from the OH), if the OH is converted to a double bond to the carbon, then a C-C bond would need to be broken (since carbon cannot have 5 bonds).
 
ldc3 said:
If you took the hydrogen from the oxygen and another hydrogen from a non-adjacent carbon atom, you would then need to connect the oxygen to something and the carbon to something. Also, taking a hydrogen from non-adjacent carbon takes more energy since the oxygen (without a hydrogen) transfers some of it charge to the adjacent carbon, which makes the adjacent hydrogen easier to remove.

Since there are only C-C bonds on a tertiary alcohol (aside from the OH), if the OH is converted to a double bond to the carbon, then a C-C bond would need to be broken (since carbon cannot have 5 bonds).

Thanks, I understand now. I never considered that carbon would have to have 5 bonds!
 

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