Testing Point (5,4) in Triangle with 3 Given Points (1,2), (4,6), and (9,10)

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Homework Help Overview

The discussion revolves around determining whether the point (5,4) lies within the triangle formed by the vertices (1,2), (4,6), and (9,10). Participants are exploring methods to assess the position of the point relative to the triangle's boundaries.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster outlines a method involving inequalities derived from the triangle's sides to test the point's position. Some participants affirm the validity of this approach while questioning if it is the simplest method available.

Discussion Status

Participants are actively engaging with the problem, with some suggesting that visual representation through graphing could aid in understanding the inequalities and the point's location. There is no explicit consensus on the best method yet, but the discussion is progressing with constructive feedback.

Contextual Notes

Participants are operating under the assumption that the three given points are vertices of a triangle, and there is a focus on the conditions necessary for the point to be considered inside the triangle.

forty
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Given 3 points of the triangle:
(1,2)
(4,6)
(9,10)
Determine if point (5,4) belongs to triangle (is located inside the triangle).

the only way i can think of doing this is as follows but there must be a more sound way.

so you have lines:
(1,2)->(4,6)
(4,6)->(9,10)
(1,2)->(9,10)

you need all 3 of the following to hold true for point (5,4)

y <= 4/3x + 2/3 (true)
y >= x + 1 (false)
y <= 4/5x + 14/5 (false)



any help greatly appreciated.
 
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If by "Given 3 points" you really mean "Given 3 vertices", then your basic approach is very good. As long as you identified the correct lines, then you can set up the suitable inequalities and determine the necessary truths for the conditions.

You can easily check about the point by actually drawing the whole graph.
 
Last edited:
Yes I do mean vertices. So this is pretty much the simplest way of going about it?

Thanks.
 
forty said:
Yes I do mean vertices. So this is pretty much the simplest way of going about it?

Thanks.

Make the graph of the inequalities; this can help you to explain the proof AND to show the proof graphically. Either the point to test is within the inequalities region or it is not within the inequalities region.
 

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