Texas Hold'em: Probability of Full House

[c1gipe]

i have looked all over the internet and found a ton of different answers to this question so i will try and ask it here:

in texas holdem
what is the probability of getting a full house after all 5 cards are delt
both of the cards delt to you have to make up the full house

 

[RustyZ32]

Try wiki next time

http://en.wikipedia.org/wiki/Poker_probability
http://en.wikipedia.org/wiki/Poker_probability_%28Texas_hold_%27em%29

 

[c1gipe]

ya i found that but I've always been told not to trust wiki. (i do anyway) But my question was how to figure it out if both your hole cards have to play. so you can't play the 5 cards on the board. you can only play 3 of them. this seems really easy but I am getting confused just as easy

 

[c1gipe]

sorry, I've realized that I've been lazy and haven't contributed

there are 16 combinations of having A and K
6 ways to have AA
6 ways to have KK

these are the only possible starting hands so there are 28/52 cards to pick from the first card and 27/51 possible for the second card.

so the probability of having a qualifying starting hand is 28/52 x 27/51 = 63/221

for the extra 5 cards on the board there are 26 possibilities with 50 cards remaining.
this is where i get lost
do i just 26/50 x 25/49 x 24/48?

then that number is the probability?