The area of a square with right triangle inside it

[JasonHathaway]

Homework Statement

I need to find the area of the square in the following figure:

Homework Equations

Basic Trig relations.

The Attempt at a Solution

I aimed to find the length of BC, but first I had to find the unknowns of the right triangle CDE, which are EC=5m, <DCE=36.86ْ , <DEC=53.13ْ .

Then I thought that I can use some trig relation for angles to get <BDC and BCD respectively (since the angles of the square are all 90ْ).

And that's where I am stuck. Any help?

 

[phinds]

figure shows as a broken link

 

[JasonHathaway]

Just fixed it. Sorry about that.

 

[phinds]

Hm ... interesting problem. It seems as though there's likely to be some trick to it that you are not seeing, but whatever it is, I'm not seeing it either.

 

[ehild]

The upper two right triangles AED and BDC are similar. Look at the angles.

 

[LCKurtz]

Call BC = s, DB = y, and AD = s-y. It's easy to get two equations in s and y.

 

[JasonHathaway]

I got it now. Thank you everyone for your help. I really appreciate it.