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The average distance between two particles in a 1d box

  1. Feb 21, 2013 #1
    1. The problem statement, all variables and given/known data

    (i) Write an expression for the wave function of 2 particles in a 1D box. Assume that
    their masses are the same, m, and that the box size is a = 1. What are the energy
    states? (Comment: The particles are distinguishable)
    (ii) Write an expression for the average distance between the particles hdi, quantum
    mechanically.

    2. Relevant equations

    Wave function = 2sin(n1x1pi)sin(n2x2pi) for part 1 and energy levels are ((n1)^2 +(n2)^2))* h^2/4m

    3. The attempt at a solution
    I use <d> as an operator, and i try to operate it on the function but i dont know how to operate <d>, it wasnt taught in class and i cant find it in the text book. is d =x2-x1. How can i find the average distance between two non interacting particles??? there are no restrictions to the distance at all. They can be on top of each other? how to do it, i cant show anymore work because i dont know what to do lol.
     
  2. jcsd
  3. Feb 22, 2013 #2

    TSny

    User Avatar
    Homework Helper
    Gold Member

    Hello, pahtakus. Welcome to PF!

    Unless I'm overlooking something, I think your expression for the energy levels is off by a factor of 2.

    My interpretation of distance between the particles would be the absolute value of x2 - x1. So, your distance operator would be d = |x2-x1|. The average distance between the particles would then be the expectation value of d using your wavefunction. It's not clear from the statement of the problem if you just need to write the integral representing the expectation value or if you must go further and evaluate the integral.

    The only restriction on the locations of the particles is that they must remain in the box. Yes, the particles can be on top of each other!
     
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