The Cliff Diver - Projectile motion

[Bottomsouth]

Homework Statement

A swimmer dives off a cliff with a running horizontal leap. What must her minimum speed be just as she leaves the top of the cliff so that she will miss the ledge at the bottom which is 1.5 m wide and 9.5m below the top of the cliff.

Homework Equations

X=V0xT Y=-1/2gt^2

The Attempt at a Solution

I have X=1.5 and Y=9.5

9.5=-1/2*9.8*t^2
1.5=V0x*t

From there I am lost, I've tried squaring T and so on. Any help is appreciated.

 

[Delphi51]

Solve the first equation for the time. Substitute it into the second to find the Vo.

 

[Bottomsouth]

9.5=-1/2*9.8*t^2
9.5=-4.9*t^2
1.93=t^2
t=1.389

1.5=Vox*1.389
1.08=Vox

Does this sound right?

 

[Delphi51]

Looks good!
In case your marker is picky, it would be a good idea to deal with the extra minus sign in the first part. Either think of "down" as positive and not use any minus signs, or put a minus sign on the 9.5 to indicate it is down.