The field just outside a metal ball

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SUMMARY

The charge residing on a 3.22 cm radius metal ball, with an electric field of 2.72×10^2 N/C pointing toward it, is calculated to be approximately -3.14×10^-11 C. The formula used for this calculation is derived from the equation E = k*q/r^2, where E is the electric field, k is Coulomb's constant (8.99×10^9 N m²/C²), and r is the radius of the ball in meters. The negative sign of the charge indicates that the ball is negatively charged, as the electric field points toward the object.

PREREQUISITES
  • Understanding of electric fields and their directionality
  • Familiarity with Coulomb's law and Gauss's law
  • Basic knowledge of unit conversions (cm to m)
  • Proficiency in algebraic manipulation of equations
NEXT STEPS
  • Study the implications of negative charge in electric fields
  • Learn more about Gauss's law and its applications in electrostatics
  • Explore the relationship between electric field strength and charge density
  • Investigate the effects of different geometries on electric fields
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Students studying electromagnetism, physics educators, and anyone interested in understanding electrostatic principles and calculations.

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Homework Statement



The field just outside a 3.22 cm radius metal ball is 2.72×10^2N/C and points toward the ball. What charge resides on the ball?

Homework Equations



E = k*q/r^2



The Attempt at a Solution



q = E*r^2/k

q = ( 2.72*10^2 N/C )* (0.0322 m^2) / 8.99*10^9

= 3.14*10^-11 C


The computer says I'm giving it the wrong answer...is there something wrong with what I did?


Thanks
 
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The magnitude of your answer seems correct...thats what Gauss's law gives ...
but i think the charge is negative because the field is pointing towards the ball...try it...
 

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