Inverse Square Law: Calculating Intensity at Different Distances

Click For Summary
SUMMARY

The discussion focuses on applying the Inverse Square Law to calculate intensity from a point source of infrared waves and light from a candle. For the first problem, given an intensity of 4 Mw−2 at a distance of 2 kilometers, the intensity at 1 meter can be calculated using the formula I2 = I1 * (d1^2 / d2^2). The second problem involves calculating the intensity of light from a candle, starting with an intensity of 20.0 units at 3.0 meters and determining the reading at 1.0 meter using the same inverse square relationship. The importance of manipulating fractions in these calculations is emphasized.

PREREQUISITES
  • Understanding of the Inverse Square Law
  • Basic algebra skills for manipulating equations
  • Familiarity with intensity measurements in watts per square meter (Mw−2)
  • Knowledge of distance measurement in meters
NEXT STEPS
  • Review the Inverse Square Law in physics textbooks
  • Practice solving equations involving fractions
  • Explore intensity calculations in different contexts, such as sound and light
  • Learn about the applications of the Inverse Square Law in real-world scenarios
USEFUL FOR

Students studying physics, educators teaching the Inverse Square Law, and anyone interested in understanding intensity calculations in wave propagation.

emtis
Messages
1
Reaction score
0

Homework Statement


Problem One: Two kilometres away from a point source of infrared waves, the intensity is 4 Mw−2. Calculate the intensity 1m away from the source.

Problem two: Light from a candle has an intensity of 20.0 units when a meter is placed 3.0m away. What is the reading on the light meter when it is brought to 1.0 m away?


Homework Equations


t00ow.jpg

7zU6j.gif


The Attempt at a Solution


Yeah, about that. I'm not really sure where to start. I mean, I have the answers with me, and I think I am able to fill in the values for the inverse square law, but I don't know how to manipulate the equation with fractions to get the answer that I want. I always struggle here, because I ****ing hate fractions and I can't seem to get one thing write with them. I'd like to see the solution with respect to the given formula above please.
 
Physics news on Phys.org
Look at the first problem. You are given the intensity and distance for one measurement; let those be ##I_1## and ##d_1## respectively. You are also given another distance, and you want to find the intensity at that spot; let those be ##d_2## and ##I_2##. You have to solve the equation you have above for ##I_2##, and then plug in the numbers you have to get your answer.
 
If your problem is with fractions than I think you should go back to basics and solve many more fraction problems from some introductory text that includes lots of examples and exercises.
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
3K
Replies
8
Views
2K
  • · Replies 5 ·
Replies
5
Views
4K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 8 ·
Replies
8
Views
4K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 33 ·
2
Replies
33
Views
3K