The Kirchhoff diffraction formula with small wavelength

In summary, the fresnel-kirchhoff diffraction formula can explain diffraction and also produce results for relatively small wavelength and large width slit. However, when the wavelength is very small, the resulting equation may not match the expected value. One suggestion is to try using a circular aperture and an observation point directly on the axis for easier calculations. It is expected that the diffraction equations will show a shadow when using a single point source on one side of the aperture, but it may be difficult to prove for the general case due to the complexity of the equations.
  • #1
zhouhao
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Homework Statement


The fresnel-kirchhoff diffraction formula could explain diffraction,I think it should also produce the result with relatively small wavelength and large width slit in which case there is no diffraction.
730px-_Kirchhoff_1a.svg.png

Homework Equations


##U(P)=\frac{ia}{2\lambda}\int_S\frac{e^{ik(s+r)}}{sr}[(cos(n,r)-cos(n,s)]dS##

The Attempt at a Solution


when ##\lambda##(wavelength) is very small,the ##U(P)## would very large and seems not equal to ##\frac{ae^ir_{P_0P}}{r_{P_0P}}##
 
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  • #2
One suggestion would be to try it for an observation point that is directly on axis, and use a circular aperture so that the diffraction equations are readily workable. I do expect the diffraction equations for small wavelength and large aperture would give very nearly a shadow when using a single point source on one side of the aperture, but the equations are cumbersome enough, that it might be somewhat difficult to show for the general case.
 
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