The Kirchhoff diffraction formula with small wavelength

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SUMMARY

The discussion focuses on the application of the Fresnel-Kirchhoff diffraction formula in scenarios involving small wavelengths and large-width slits. It asserts that for very small wavelengths, the resulting diffraction pattern approaches a shadow effect, particularly when using a circular aperture. The formula presented, U(P)=\frac{ia}{2\lambda}\int_S\frac{e^{ik(s+r)}}{sr}[(cos(n,r)-cos(n,s)]dS, is highlighted as complex yet essential for understanding diffraction behavior in these conditions. The suggestion to analyze the scenario with an observation point directly on axis is noted as a practical approach to simplify calculations.

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Homework Statement


The fresnel-kirchhoff diffraction formula could explain diffraction,I think it should also produce the result with relatively small wavelength and large width slit in which case there is no diffraction.
730px-_Kirchhoff_1a.svg.png

Homework Equations


##U(P)=\frac{ia}{2\lambda}\int_S\frac{e^{ik(s+r)}}{sr}[(cos(n,r)-cos(n,s)]dS##

The Attempt at a Solution


when ##\lambda##(wavelength) is very small,the ##U(P)## would very large and seems not equal to ##\frac{ae^ir_{P_0P}}{r_{P_0P}}##
 
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One suggestion would be to try it for an observation point that is directly on axis, and use a circular aperture so that the diffraction equations are readily workable. I do expect the diffraction equations for small wavelength and large aperture would give very nearly a shadow when using a single point source on one side of the aperture, but the equations are cumbersome enough, that it might be somewhat difficult to show for the general case.
 

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