The Mass of a Black Hole versus its volume

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Homework Help Overview

The discussion revolves around the relationship between the mass and volume of a black hole, specifically exploring how to determine the mass required for a black hole's density to equal that of water. The original poster expresses frustration over calculating the volume and radius using the Schwarzschild radius formula.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to relate mass, volume, and density but struggles with the calculations due to missing values. Some participants explore the implications of the Schwarzschild radius and its application to the problem. Others question the validity of calculating black hole volume using Euclidean geometry.

Discussion Status

Some participants have provided guidance and attempted calculations, while others are seeking clarification on specific formulas and their origins. Multiple interpretations of the problem are being explored, particularly regarding the minimum mass of a black hole and the nature of its volume.

Contextual Notes

There are discussions about the assumptions underlying the calculations, particularly regarding the nature of space within a black hole and the applicability of classical volume formulas. The original poster's frustration highlights the complexity of the problem and the need for further clarification on certain concepts.

oldspice1212
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A clump of matter does not need to be extraordinarily dense in order to have an escape velocity greater than the speed of light, as long as its mass is large enough. You can use the formula for the Schwarzschild radius Rs to calculate the volume 4/3piRs^3 inside the event horizon of a black hole of mass M.

What does the mass of a black hole need to be in order for its mass divided by its volume to be equal to the density of water (1 g/cm^3) ?So I have the density which = mass/volume = 1 g/cm^3

I know I'm suppose to find the mass but then how do I know what the volume is?
If the volume formula is 4/3pir^3, I'm having trouble with finding radius now, since I don't have the volume, I'm really frustrated about this question.Also using Schwarzschild radius formula Rs = 2Gm/c^2 seems useless because I don't have mass now?! Err so I need mass and volume but all I have is density?!
 
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SOLVED IT...

Rs = (3km)x M/Msun convert 3km to 3x10^5 cm...

density = mass/volume = M/ 4/3 piR^3

density = 3M/ 4pi ((3x10^5 cm)M/Msun)^3

...

M/Msun = root (3Msun/4pi(density)(2.7x10^16))

= 1.33x10^8 Msun

Took a while but finally got it, and this is how if anyone is interested.
 
With that you could calculate the minimum possible mass of a black hole. Is there one? Could you just shove two neutrons together really hard and have them form an event horizon?
 
Thank you Oldspice1212! I was looking for how to solve this question too!

Could you tell me where you got Rs = 3km x M/Msun? and where the 3km came from?



As well, for this section of what you wrote: "M/Msun = root (3Msun/4pi(density)(2.7x10^16))"

I plugged this in as 3rdroot(3*(2*10^30) / 4pi(1)(2.7*10^16)) but I did not get 1.33*10^8 Msun, Did I do it correctly?
 
What would be the minimum mass of a black hole with a volume of 225 m^3
 
JustinAlger said:
What would be the minimum mass of a black hole with a volume of 225 m^3
Welcome to PF.

Can you use the equations in the posts above to answer your question?
 
Note also that this question doesn't really make sense, since the interior volume of a black hole can't be calculated using a Euclidean formula. That space isn't flat there is kind of an important point...
 
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