The Moon And The Earth, Acceleration ( Question Answered, Just need check )

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SUMMARY

The discussion focuses on calculating the distance between the center of the Earth and the center of the Moon using gravitational acceleration and orbital period. The acceleration due to gravity at Earth's surface is 9.80 m/s², and the Moon's orbital period is 27.32 days. The user attempts to derive the distance using the equations R = 2π/(T*v) and a = v²/R, but receives feedback indicating that the second equation does not logically follow from the first. The user seeks clarification on eliminating the square root of R from their expressions.

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RajdeepSingh7
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The Moon And The Earth, Acceleration ( Question Answered, Just need check ) :D

The question we were given was.:

Given the facts that (i) the acceleration due to gravity at the surface of the Earth is 9.80 m/s2, (ii)
the Moon orbits the Earth every 27.32 days, and (iii) the radius of the Earth is 6.38 × 106 m,
estimate the distance, R, between the centre of the Earth and the centre of the Moon. (Hint:
write down the relevant equations and rearrange them to give expressions for R. You will find
that many of the variables cancel out).

I have attempted it and this is my answer:
2pi*R=T*v
R=2pi/(T*v)
a=v^2/R v=sqrt(aR)
R*sqrt(R)=2pi/(T*sqrt(a)) (a=acceleration(9.8m/s2), v=velocity, T=period time(27.32 days))

Is this the correct method, could anyone please tell me and clarify?
And also, how do I get rid of the sqrt(R), is there anyway to give the expression just in terms of R?

Any Help and Contribution will be greatly appreciated.
:D
 
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RajdeepSingh7 said:
I have attempted it and this is my answer:
2pi*R=T*v
R=2pi/(T*v)
Your approach is correct however the second equation does not follow from the first. Try again.
 

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