jacobbry
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- TL;DR Summary
- I would like to know all the physical components involved in the electron double slit experiment. Including the observer, detection and effects that each of these have on the electron.
I understand the results of the electron double slit experiment and wish to find out why it is the case. I need to start with a more full understanding of the physical interactions taking place:
What is the “observer”, I understand that high energy light is used as an observer sometimes but what are others and exactly how do they all effect the electron.
What is the detection screen made or and what specifically does it detect, I know that the mass of an electron is far to small to be detected so the obvious answer is that the detection screen detects the charge or the electromagnetic field/ waves of the electron.
At what stage in the experiment is the electron observed and how does the point it is observed alter the outcome of the experiment.
If an photoelectron collides with a high energy photon what are the changes to the electron.
I believe the answer to these questions could really help with my understanding of the physical components at play so I would appreciate anyone taking the time to answer my questions.
What is the “observer”, I understand that high energy light is used as an observer sometimes but what are others and exactly how do they all effect the electron.
What is the detection screen made or and what specifically does it detect, I know that the mass of an electron is far to small to be detected so the obvious answer is that the detection screen detects the charge or the electromagnetic field/ waves of the electron.
At what stage in the experiment is the electron observed and how does the point it is observed alter the outcome of the experiment.
If an photoelectron collides with a high energy photon what are the changes to the electron.
I believe the answer to these questions could really help with my understanding of the physical components at play so I would appreciate anyone taking the time to answer my questions.
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