The quadratic covariation of Brownian motion and poisson process

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SUMMARY

The quadratic covariation of Brownian motion B(t) and a Poisson process N(t) is definitively zero. This conclusion arises from the nature of the two processes: Brownian motion is a continuous process, while the Poisson process is characterized by discrete jumps. The formula [B,N] = [B,N]^{c} + ΔB ΔN confirms this, as both the continuous part [B,N]^{c} and the jump components ΔB and ΔN equal zero, leading to the overall result of zero quadratic covariation.

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knightzero
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Hi:
I want to know the quadratic covariation of Brownian motion B(t) and poisson process N(t).Is it B(t)?
Thanks !
 
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I think it should be zero because Brownian motion is a continuous process without jump components while Poisson is a quadratic pure jump process with continuous part being constant. Hence, [B,N] = [B,N]^{c} + \Delta B \Delta N = 0 + 0 = 0 where [B,N]^{c} is the continuous part of quadratic covariation process.
 

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