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This is an aside (and way too early) but if the "theorem" of that paper is correct would that imply that one is left with either the Everett or de Broglie/Bohmian versions?
The key issue here is whether we should regard quantum mechanics as incomplete compared to a physical theory that would be possible (Einstein's view), or simply incomplete compared to our naive preconceptions about what a physical theory ought to be (i.e., we should not expect to completely represent the properties of a system with a mathematical object, either because the properties can't be represented that way, or don't exist in the first place). The article appears to consider it a "mild assumption" to take the former view, so does so, and shows that the ensemble view is inconsistent with that view. But I see nothing inconsistent in the ensemble view with the latter stance, and to me, the key question is not ensemble vs. real state, it is that first issue. So if we must take a stance on the first issue to follow their proof, then we have already ducked the most important question.Fredrik said:I don't really have a problem with that. If I thought the rest of the argument was sound, I would be pointing out that it's not obvious that such a theory exists, but I would still find their result interesting.
That is OK within the assumptions they are making to give their argument. They are saying that if there are "properties" of individual systems, then either knowledge of the properties suffices to specify the state vector, or it doesn't. If it does, then each state vector has a correspondence to its own unique possible collection of properties-- i.e., if there are properties of individual systems, then the state vector limits the possibilities for those properties, so it does convey information about individual systems. If knowledge of the properties doesn't uniquely specify the quantum state, then it must be possible for the same properties to be associated with two different state vectors. That's what they use to get a contradiction. I think they are saying that if two state vectors connect with all different properties, those vectors have to be orthogonal, but by assumption they have two states that are not orthogonal, so they must have properties that appear with both state vectors-- unless the state vectors are themselves properties.What bothers me is that they're saying that if the second view of QM (the statistical one) is correct, i.e. if a state vector doesn't accurately represent the properties of a single system, then the state vector isn't determined by λ.
I'm not sure I understood what you consider the key issue. Is it the existence (vs. non-existence) of that theory in which a mathematical object λ represents all the properties of the system? That's an interesting issue, but (as you know) it's not what the article is about.Ken G said:The key issue here is...
Right. That's the part of the argument that I summarized as "If properties do not determine probabilities, then we're screwed. Therefore, properties determine probabilities." I have no problem with that part of it. In fact, I consider "properties do not determine probabilities" to be an absurd statement on its own. They didn't even have to derive a contradiction from it. (If λ doesn't determine all the probabilities (and then some), then why would anyone call it "all the properties of the system"). To me, their argument is very much like proving that 1≠1 implies that 2≠2, and then concluding that "Sons of Anarchy" isn't the best thing on TV right now.Ken G said:If knowledge of the properties doesn't uniquely specify the quantum state, then it must be possible for the same properties to be associated with two different state vectors. That's what they use to get a contradiction.
Fredrik said:I'm not sure I understood what you consider the key issue. Is it the existence (vs. non-existence) of that theory in which a mathematical object λ represents all the properties of the system? That's an interesting issue, but (as you know) it's not what the article is about.
Right. That's the part of the argument that I summarized as "If properties do not determine probabilities, then we're screwed. Therefore, properties determine probabilities." I have no problem with that part of it. In fact, I consider "properties do not determine probabilities" to be an absurd statement on its own. They didn't even have to derive a contradiction from it. (If λ doesn't determine all the probabilities (and then some), then why would anyone call it "all the properties of the system"). To me, their argument is very much like proving that 1≠1 implies that 2≠2, and then concluding that "Sons of Anarchy" isn't the best thing on TV right now.
I have always been thinking that the statistical view (ensemble interpretation) and "properties determine probabilities" are both true. It has never even occurred to me to consider that a complete specification of all the system's properties would be insufficient to determine the probabilities. Where did they get the idea that the statistical view implies that properties are insufficient to determine probabilities? I don't think it implies anything like that. What it says is that a complete specification of the preparation procedure determines the probabilities, but is insufficient to determine the properties (if it makes sense to talk about properties at all).
Fredrik said:OK, new summary. Simplified.
They are comparing two different schools of thought:I say that
Their argument against the second view goes roughly like this:
- A state vector represents the properties of the system.
- A state vector represents the statistical properties of an ensemble of identically prepared systems, and does not also represent the properties of a single system.
Suppose that there's a theory that's at least as good as QM, in which a mathematical object λ represents all the properties of the system. Suppose that view 2 above is the correct one. Then λ doesn't determine the probabilities of all possible results of measurements.[/color] Yada-yada-yada. Contradiction! Therefore view 2 is false.
Am I wrong about something?
- The entire article rests on the validity on the statement in brown, which says that view 2 somehow implies that "all the properties" are insufficient to determine the probabilities. (If that's true, then why would anyone call them "all the properties"?)
- The brown statement is a non sequitur. (A conclusion that doesn't follow from the premise).
- The only argument the article offers in support of the brown claim, doesn't support the brown claim at all.
That's what the authors of the article are saying. To me it seems like a completely unrelated assumption. Maybe I'm missing something.martinbn said:I am probably missing something, but isn't the statement in brown what the difference between the two schools of thought is?
They are comparing two different schools of thought:
A state vector represents the properties of the system.
A state vector represents the statistical properties of an ensemble of identically prepared systems, and does not also represent the properties of a single system.
That's definitely the difference.bohm2 said:Isn't the bolded part the difference or am I missing something?
Fredrik said:Am I wrong about something?
http://blogs.discovermagazine.com/c...lace-on-the-physicality-of-the-quantum-state/
Why the quantum state isn’t (straightforwardly) probabilistic
...
Consider, for instance, a very simple interference experiment. We split a laser beam into two beams (Beam 1 and Beam 2, say) with a half-silvered mirror. We bring the beams back together at another such mirror and allow them to interfere. The resultant light ends up being split between (say) Output Path A and Output Path B, and we see how much light ends up at each. It’s well known that we can tune the two beams to get any result we like – all the light at A, all of it at B, or anything in between. It’s also well known that if we block one of the beams, we always get the same result – half the light at A, half the light at B. And finally, it’s well known that these results persist even if we turn the laser so far down that only one photon passes through at a time.
According to quantum mechanics, we should represent the state of each photon, as it passes through the system, as a superposition of “photon in Beam 1″ and “Photon in Beam 2″. According to the “state as physical” view, this is just a strange kind of non-local state a photon is. But on the “state as probability” view, it seems to be shorthand for “the photon is either in beam 1 or beam 2, with equal probability of each”. And that can’t be correct. For if the photon is in beam 1 (and so, according to quantum physics, described by a non-superposition state, or at least not by a superposition of beam states) we know we get result A half the time, result B half the time. And if the photon is in beam 2, we also know that we get result A half the time, result B half the time. So whichever beam it’s in, we should get result A half the time and result B half the time. And of course, we don’t. So, just by elementary reasoning – I haven’t even had to talk about probabilities – we seem to rule out the “state-as-probability” rule.
Indeed, we seem to be able to see, pretty directly, that something goes down each beam. If I insert an appropriate phase factor into one of the beams – either one of the beams – I can change things from “every photon ends up at A” to “every photon ends up at B”. In other words, things happening to either beam affect physical outcomes. It’s hard at best to see how to make sense of this unless both beams are being probed by physical “stuff” on every run of the experiment. That seems pretty definitively to support the idea that the superposition is somehow physical.
That's the same thing.DevilsAvocado said:I don’t know because I haven’t read the full paper yet (isn’t this just typical), but is this really about ensembles (and the Ensemble interpretation)? Isn’t it about "state-as-probability" vs. "state-as-physical"?
Maybe it seems that way, but this is not implied by my definition of the second "school of thought" above.Wallace said:But on the “state as probability” view, it seems to be shorthand for “the photon is either in beam 1 or beam 2, with equal probability of each”.
Fredrik said:The entire article rests on the validity on the statement in brown, which says that view 2 somehow implies that "all the properties" are insufficient to determine the probabilities. (If that's true, then why would anyone call them "all the properties"?)
Fredrik said:That's the same thing.
"state-as-probability" = "ensemble interpretation" = "statistical interpretation" = "Copenhagen interpretation" (although some people will insist that the CI belongs on the "state-as-physical" side).
The stuff I'm talking about is covered on the first one and a half pages, so you don't have to read the whole thing. I haven't, and I'm not going to unless someone can convince me that I'm wrong.
Fredrik said:Maybe it seems that way, but this is not implied by my definition of the second "school of thought" above.
This is however a point that different statistical/ensemble interpretations disagree about. Ballentine's 1970 article "The statistical interpretation of quantum mechanics" explicitly made the assumption that all particles have well-defined positions, even when their wavefunctions are spread out. That assumption is notably absent from Ballentine's recent textbook, so maybe even he has abandoned that view.
Right, I'm saying that to me, that's the real issue here. So I don't find the conclusions in the article to be particularly important, because they require making assumptions that I doubt are reliable. It seems to me that people who make those assumptions have already chosen a specific approach to interpreting quantum mechanics, so whether or not the ensemble interpretation is consistent with that specific approach is only interesting to people inclined to choose both the ensemble interpretation and that specific approach (and I don't count myself in either of those groups). But we can still analyze whether the paper reaches valid conclusions that people in both those groups should worry about.Fredrik said:I'm not sure I understood what you consider the key issue. Is it the existence (vs. non-existence) of that theory in which a mathematical object λ represents all the properties of the system? That's an interesting issue, but (as you know) it's not what the article is about.
But we aren't screwed in that case, we're just fine. If someone writes an article tomorrow that proves that quantum mechanics is not consistent with the attitude that properties determine probabilities, does quantum mechanics suddenly not work to predict our experiments? Nothing that we use quantum mechanics for requires that properties determine probabilities, instead what we need is for state vectors to determine probabilities, because that's how quantum mechanics works. Properties are completely irrelevant to doing physics, they are purely philosophical, and somewhat naive philosophy at that. That's my primary objection-- the fixation on the importance of "properties" is a very specific interpretation choice, but physics only requires that "properties" be a useful organizational principle, it never requires that we take this concept seriously, and certainly doesn't need us to make any mathematical proofs based on the notion. I doubt that systems actually have properties at all, that's just how we like to think about them.Right. That's the part of the argument that I summarized as "If properties do not determine probabilities, then we're screwed."
It's not absurd if the whole concept of properties is already viewed as absurd. I agree it would be absurd to believe in properties that do not determine probabilities, for what would be the point in believing in properties like that, but the rational alternative is to view the whole "property" concept as an effective notion we create to make progress, like all the other effective notions we make in physics and should certainly have learned by now not to take so seriously as to prove things based on them as axioms. Or put differently, when we use them as assumptions and prove things, we should do it from the point of view of showing why we shouldn't have assumed that thing in the first place-- it forces us to imagine we are dictating to nature.In fact, I consider "properties do not determine probabilities" to be an absurd statement on its own.
This is an important question, and demands closer scrutiny. They seem to be saying they have proven that your position is internally inconsistent-- you cannot maintain both that a state vector is only a claim on the properties of an ensemble, not a claim on the properties of an individual system, and that properties of individual systems determine the probabilities for that system. I'm not sure exactly what they think the statistical interpretation is, but the one you expound sounds like a standard version, so they must feel that they have proven it to be internally inconsistent.I have always been thinking that the statistical view (ensemble interpretation) and "properties determine probabilities" are both true. It has never even occurred to me to consider that a complete specification of all the system's properties would be insufficient to determine the probabilities. Where did they get the idea that the statistical view implies that properties are insufficient to determine probabilities?
That's my point too, because quantum mechanics (and physics) only involves a connection between a preparation procedure and probabilities. That's it, that's all the physics that's in there. There aren't any "properties" in the physics, that's some kind of added philosophical baggage that can be used to prove things but doesn't convince me it belongs there at all, so why should we care what can be proven from it?What it says is that a complete specification of the preparation procedure determines the probabilities, but is insufficient to determine the properties (if it makes sense to talk about properties at all).
Ken G said:That's my point too, because quantum mechanics (and physics) only involves a connection between a preparation procedure and probabilities. That's it, that's all the physics that's in there. There aren't any "properties" in the physics, that's some kind of added philosophical baggage that can be used to prove things but doesn't convince me it belongs there at all, so why should we care what can be proven from it?
For these reasons and others, many will continue to hold that the quantum state is not a real object. We have shown that this is only possible if one or more of the assumptions above is dropped. More radical approaches (e.g. Fuchs) are careful to avoid associating quantum systems with any physical properties at all.
bohm2 said:Their assumptions:
1. If a quantum system is prepared in isolation from the rest of the universe, such that quantum theory assigns a pure state, then after preparation, the system has a well defined set of physical properties.
No, either |0> or |+>. The latter is a superposition of |0> and |1>. |0> and |1> are the eigenstates of some operator, like a spin component operator. But they have one preparation device that always leaves the system in state |0> and another that always leaves the system in state |+>.StevieTNZ said:I am assuming that by a 'well defined set of physical properties' that the system is in a definite state? That is the impression I'm getting from what they wrote under Figure 1, that the system is in either |0> or |1>.
alxm said:... By extension the main result here is that for two identical systems prepared in isolation from each other, the result predicted by quantum mechanics for a joint measurement cannot be enforced merely by knowing lambda1 and lambda2, since it doesn't tell you how you got it there, which has importance for what you measure.
But if lambda is actually the wave-function (or can tell you it), then obviously there's no problem.
DevilsAvocado said:[my bolding]
Isn’t this exactly what David Wallace describes in his simple https://www.physicsforums.com/showthread.php?p=3623347#post3623347"?
Thanks for posting this. This is a very nice explanation. I've been thinking that they probably meant something other than this, since they weren't very explicit about it. Now I'm thinking that this must have been what they meant.alxm said:The way I read it, what they mean by "all the properties" is some set of hidden variables or similar that are sufficient to determine the outcome of any measurement. The "real" state is represented by lambda, and the quantum state is just a classical statistical distribution over the various "lambda states". It's not a classical analogy, it is classical. Although whatever goes into putting the system into a particular lambda state is not necessarily deterministic or local or whatever; only point is that QM tells us that certain processes will allow us to prepare states with certain distributions.
So knowing lambda doesn't tell you how you got there.
alxm said:Well, the conclusion is the same. But it seems to me that he's more describing the ordinary double-slit experiment.
One key difference between that and what's being described in the paper, is that the states of the double-slit/half-silvered mirror paths aren't created independently of each other. It's quite a bit less weird to have "spooky action at a distance" between a single state "split" in two, than between two states prepared in isolation that never had any interaction. That's what seems to be the main novelty here.
zonde said:Ensemble interpretation says that QM works for ensembles but does not work for individual systems.
This paper under discussion says that indeed ensemble interpretation leads to contradiction if QM is applicable to individual systems (thought experiment in fig.1). So what?
Fredrik said:This is wrong, and it's also a very different claim from the one made by this article. A state vector is certainly an accurate representation of the properties of an ensemble of identically prepared systems. It's conceivable that it's also an accurate representation of the properties of a single system. The article claims to be proving that it's wrong to say that it's not a representation of the properties of a single system.
This is even more wrong. Also, if you want to discuss these things, please keep them to the other thread where you brought this up.