The Rocket Equation: Unraveling the Mystery

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SUMMARY

The discussion focuses on the derivation and understanding of the rocket equation, specifically addressing the constant velocity of exhaust relative to the rocket body. It clarifies that while the mass of the rocket decreases at a constant rate due to the mass flow rate of the propellant, the exhaust velocity observed from the rocket's frame of reference remains constant. The equation for acceleration, a(t) = F[1/m(t)], is established, where F is the constant force exerted by the propellant and m(t) is the rocket's mass at time t. This understanding reinforces the concept that the propelling mechanism is part of the rocket system, allowing for consistent observations of exhaust velocity.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with the concept of mass flow rate
  • Basic knowledge of calculus for understanding time-dependent equations
  • Knowledge of the rocket equation and its components
NEXT STEPS
  • Study the derivation of the rocket equation in detail
  • Explore the implications of variable mass systems in classical mechanics
  • Learn about thrust and its calculation in rocket propulsion
  • Investigate the effects of gravitational forces on rocket acceleration
USEFUL FOR

Aerospace engineers, physics students, and anyone interested in understanding rocket propulsion and the dynamics of accelerating systems.

adphysics
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In deriving the rocket equation, there is one part I don't understand. The velocity of exhaust with respect to the body is assumed to be constant, where:

v(exhaust wrt body)=v(exhaust wrt inertial)-v(body wrt inertial)

So assuming a constant mass flow rate, the rocket propellant exerts a constant force on the rocket and hence in space, uniform acceleration. But how can an observer on the accelerating rocket observe the rocket propellant being ejected with a constant velocity?
 
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adphysics said:
... the rocket propellant exerts a constant force on the rocket and hence in space, uniform acceleration.
This is not correct. The mass of the rocket decreases at a rate equal to the exhaust mass rate. The constant exhaust velocity should be w.r.t the rocket.
 
Oops. So assuming a constant mass flow rate the propellant exerts a constant force on the rocket so the rocket's acceleration increases as follows:

a(t)=F[1/m(t)] where F is a constant (until fuel runs out) where m(t) is the mass of the rocket at time t.

m(t)=m(initial)-bt where b is a constant (mass flow rate)

Hence v_rocket(t)=-Fln(m(t))/b assuming v(0)=0

But why would an observer in the rocket observe a constant propellant velocity?
 
adphysics said:
... why would an observer in the rocket observe a constant propellant velocity?
Because the propelling mechanism is in the rocket.
 
Oh, yeah. The engine is on the back of the rocket, so it accelerates with the rocket, so if an engine ejects exhaust at a velocity v, then this is what is observed from the rocket's point of view.

Now I feel somewhat embarrassed, but at least the rocket equation makes sense now.
 
adphysics said:
Now I feel somewhat embarrassed, ...
You should not. No one knows everything. You should only feel embarrassed if you refuse to ask a question out of fear of sounding stupid. Don't let your transient embarrasment prevent your permanent understanding:
adphysics said:
... the rocket equation makes sense now.
Have fun learning.
 

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