The total sum of forces in circular motion in gravitational field

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SUMMARY

The discussion focuses on understanding the net centripetal force in a gravitational field, specifically in the context of a Ferris wheel. The net centripetal force is defined as mv²/r, where m is mass, v is velocity, and r is the radius of the circular path. Participants clarify that the net force results from the combination of gravitational force and normal force acting on the riders. The conversation emphasizes the importance of recognizing how these forces interact to produce the net centripetal force necessary for circular motion.

PREREQUISITES
  • Centripetal force concepts
  • Newton's laws of motion
  • Gravitational force understanding
  • Basic circular motion principles
NEXT STEPS
  • Study the derivation of centripetal force equations
  • Learn about the role of normal force in circular motion
  • Explore gravitational force calculations in different contexts
  • Investigate real-world applications of centripetal force in amusement rides
USEFUL FOR

Physics students, educators, and anyone interested in the mechanics of circular motion and gravitational forces, particularly in practical scenarios like amusement park rides.

J.Asher
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Hello,

I am now studying centripetal force.

and the problem is that centripetal force in gravitational field.

Let's talk about Ferris-wheel ride, this ride has some rooms to carry people and fixed to the

edge of the wheel. Since it is rotating periodically, its magnitude of net force has to be

mv^2/r, right?

but this is the sum of forces. now I cannot go further.

I cannot fully understand how the force will be summed up into the net centripetal force.

Is there anyone who can help me by telling me the how the sum of the forces can finally

have the net centripetal force mv^2/r ,

(the forces might be normal force and gravitational force, right?)

waiting your answers.. thanks for reading
 
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Think about this: how is the chair attached to the Ferris wheel?
 

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