mitchell porter said:
A quark-antiquark gluon-string is just an ordinary meson. A quark-antiquark gluino-string could be a lepton, as in the sBootstrap. .
Yep, but one would need to find that a gluino string, because of some unknown, shows in low evergy as a point-particle, while a gluon string shows as an extended one. Hard to swallow, particularly because the strings have never presented a structure function similar to the experimental ones. Not the same partons, it seems :-(
I am thinking of a roadmap for the sBootstrap that could be palatable to stringers.
First, look at bosonic oriented strings and note that the SO(10) Chan Paton symmetry on it implements three generations of scalars in the tachion.
Separate mesons from diquarks by finding some oriented mesons inside this unoriented string. This could be problematic as usually the quotient goes in the reverse direction. But it could be doable.
Then argue that SO(10) is justified by a supersymmetric bootstrap: that light Dirac superpartners of these scalars must generate again the same sector. This for itself is already an argument to introduce fermions.
Now go down from D=26 to D=10 and try to keep this symmetry alive. Perhaps in the D-instanton, which has SO(10), or perhaps with some creative use of Marcus-Sagnotti fermion labels.
Now, our strings are still in some sense decolored, or SU(N-->infinity), and need to have chiral electroweak charge, instead of only electromagnetic. We should solve this when going down to D=4; the process of going from D=10 to D=9 would assign the broken electroweak components, and D=9 down to D=4 would paint the string with flying SU(3) colours plus B-L numbers.
EDIT: let me add the tables of the SO(10). The 54 down to SU(5) \times U_1(1)
<br />
54 = {15}(4) + \bar{15}(−4) + {24} (0)<br />
Then each representation goes down to SU(3) \times SU(2) \times U_2(1)
<br />
\begin{eqnarray*}<br />
15 =& (1, 3)(−6) + (3, 2)(−1) + (6, 1)(4) \\<br />
24 =& (1, 1)(0) + (1, 3)(0) + (3, 2)(5) + (\bar 3, 2)(−5) + (8, 1)(0)<br />
\end{eqnarray*}<br />
And from the two hypercharges, we can produce a charge
Q
<br />
\begin{array}{l|c |r|r|c} % a/b = 1/6 or = 2/3?<br />
flav & N& Y_1 & Y_2& Q= \frac 1{30}Y_1 - \frac15 Y_2 \\ % Q= -\frac 2{15}Y_1 - \frac15 Y_2<br />
\hline<br />
(6,1) & 6 & 4 & 4 & -2/3 \\<br />
(3,2) & 6 & 4 & -1 & +1/3 \\ <br />
(1,3) & 3 & 4 & -6 & +4/3 \\ <br />
(\bar 6,1) & 6 &-4 & -4 & +2/3\\ <br />
(\bar 3,2) & 6 & -4 & 1 & -1/3\\ <br />
(1,\bar 3) & 3 & -4 & 6 & -4/3\\ <br />
(\bar 3,2)& 6 & 0 & -5 & +1 \\<br />
(3,2) &6 &0 & 5 & -1 \\<br />
(1,1) & &&& \\<br />
(1,3)&12 &0& 0& 0 \\<br />
(8,1)& &&& \\<br />
\end{array} <br />
On the other hand, it is tempting to try some hypercharge that puts away the chiral (1,3) squark