Therefore, a = 3 and b = 5.Hydrostatic Force Homework: Find a & b

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SUMMARY

The discussion revolves around calculating hydrostatic force for an object with a volume of 30m³ floating in two different liquids. The correct hydrostatic force in the first liquid with a density of 3g/cm³ is calculated as 450,000 N, leading to a mass of 4,500 kg and a density of 1,500 kg/m³ for the object. When placed in a second liquid with a density of 1g/cm³, the hydrostatic force is determined to be 300,000 N, expressed as 3 × 105 N. The initial answer of 3 × 103 N was incorrect.

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Homework Statement


An object made entirely from one material has a volume of 30m3. It floats in a liquid of density of 3g/cm3 with only half its mass below the liquid's surface. The object is then placed in another liquid of same volume but with a density of 1g/cm3 If the final upthrust that will act on the object is expressed in the form of a × 10^{b} N give the value of a and b. [Assume g = 10m/s2]

The answer stated is 3 × 103

I got a different solution, please kindly advice.

Thanks :)

The Attempt at a Solution



Hyrdostatic force is : ρVg = 3 g/cm3 × 1000 cm3/m3 kg/g × 15m3 × 10 N/kg = 450'000 N

Since hydrostatic force = gravitational force,

The mass of the object will be : m = 45000N × 0.1 kg/N = 4500kg
The density of the object will be: ρobject = 4500kg/30m3 = 1500 kg/m3

Since it is denser than the second liquid, the hydrostatic force experienced in the second liquid will be as follow:

F= ρVg = 1 g/cm3 × 1000 cm3/m3 kg/g × 30m3 × 10 N/kg = 300'000N = 3 × 105 N
 
Last edited:
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Your answer of 3 ×105 N looks correct to me.
 
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