- #1
Maxee
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Homework Statement
A water of mass 300g has been poured into a glass of mass 100g (of specific heat capacity 970Jkg-1°C-1) in a refrigerator. How much energy must be removed to cool the liquid and the glass from 30°C to 7°C?
Homework Equations
c = Q/mΔT
The Attempt at a Solution
mwater = 300g = 0.3kg
cwater = 4180JKg-1°C-1
mglass = 100g = 0.1kg
cglass = 970Jkg-1°C-1
ΔT = -23°C
Q = ?
c = Q/mΔT => ΔT = Q/cm
...
I'm having a problem setting up the equation the right way since this isn't helping me solve my problem here. I believe I'm fundamentally thinking wrong about the problem and hence am setting it up this way. Any help would be appreciated on how to proceed with it and also, please, include the reasoning behind your decisions so I can learn to set up the problem correctly in my head. Thank you.