A Jaguar XK8 convertible has an eight-cylinder engine. At the beginning of its compression stroke, one of the cylinders contains 499 cm cubed of air at atmospheric pressure (1.01E5 Pa) and a temperature of 27.0 degrees C. At the end of the stroke, the air has been compressed to a volume of 46.2 cm cubed and the gauge pressure has increased to 2.72E6.
What is the final temperature
P1*V1/T1 = P2*V2/T2
The Attempt at a Solution
I followed the equation that I posted above. Here is what it looked like.
(1.01E5 * 499 cm cubed)/ 27 = (2.72E6 * 46.2)/x
Solving for x, I got x = (2.72E6*46.2)/1866629.63 = 66.8 degrees C
Problem is, that answer is apparently wrong. Am I missing something here?
Thanks for the help!