1. The problem statement, all variables and given/known data A well lagged calorimeter of mass 120g contains 200g of water and 50g of ice, initial at 0°C. A jet of steam is blown through the water until the water temperature reaches 30°C. Calculate the mass of steam that must condensed. The specific heat capacity of Copper: 380Jkg-1K-1 The specific heat capacity of Water: 4200Jkg-1K-1 The specific heat capacity of Ice: 2100Jkg-1K-1 The specific latent heat of fusion of Ice: 3.25x105 Jkg-1 The specific latent heat of vaporization of Water: 2.25x106Jkg-1 2. Relevant equations Q=mcΔθ Q=ml 3. The attempt at a solution My attempt was using Q=mcΔθ, for water (200x-3) x (4200) x (30) = 25200Jkg-1K-1 And similar for Ice (50x10-3)x(2100)x(30)=3150Jkg-1K-1 However to me it doesn't look like i'm going anywhere.. any help will be appreciated.