- #1
Greger
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does this look right?
for the quasistatic case you can use thermodynamics to find the temperature at any time,
for the other case you have to use dU=dW and so on since its not quasistatic
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does this look right?
for the quasistatic case you can use thermodynamics to find the temperature at any time,
for the other case you have to use dU=dW and so on since its not quasistatic
quasistatic case :
Tf=PfVf/(NKB)
under constant pressue:
Tf=2Pex(Vi-Vf)/3NkB + Ti
yea there's afew like
TV^(gamma - 1)=constant
C=NKb Tf Vf^(γ-1)=NKb TiVi^(γ-1)
Tf= Ti(Vf Vi)^(γ-1)
for γ=Cp/Cv
Tf= Ti(Vf Vi)^(Cp/Cv-1)
is that kind of what you mean?