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does this look right?
for the quasistatic case you can use thermodynamics to find the temperature at any time,
for the other case you have to use dU=dW and so on since its not quasistatic
It is correct for the constant external pressure. But what is the final temperature in the quasi-static case? It is true that T_{f}=PV_{f}/(NK_{B}) but P changes during the process. How do you get the final pressure P_{f}?
does this look right?
for the quasistatic case you can use thermodynamics to find the temperature at any time,
for the other case you have to use dU=dW and so on since its not quasistatic
Well, it is not the solution yet. You need to give T_{f} in terms of the initial and final volumes and the initial temperature. Do you know the equation that governs a quasistatic adiabatic process?quasistatic case :
T_{f}=P_{f}V_{f}/(NK_{B})
under constant pressue:
T_{f}=2P_{ex}(Vi-Vf)/3Nk_{B} + Ti
That is a good start. You can find that constant as you know the initial volume and temperature:yea theres afew like
TV^(gamma - 1)=constant
Yes, but you made a little error:C=NKb Tf Vf^(γ-1)=NKb TiVi^(γ-1)
Tf= Ti(Vf Vi)^(γ-1)
for γ=Cp/Cv
Tf= Ti(Vf Vi)^(Cp/Cv-1)
is that kind of what you mean?