1. The problem statement, all variables and given/known data An ice cube of mass 36 g at temperature -10 Celsius is placed in 360 g of water at 20 Celsius. Find thermal equilibrium temperature. [tex]\Delta[/tex]H(fusion) = 6.007 kJ mol[tex]\wedge[/tex]-1. Molar heat capacity of ice = 38 water = 75 (Joules)/(K mol) Assume no heat loss to the surroundings. 2. Relevant equations [tex]\Delta[/tex] H = n(Cp) [tex]\Delta[/tex]T q = M (Cs) delta T 3. The attempt at a solution I tried to find the thermal temperature first by using the temperature above, but I got different temperatures that were not even close to what they should be. THe thermal temperatures should be between -10 and 20, however they are going to be closer to the 20 becuase water mass is much more than mass of ice.