Thermochemistry and Equilibrium of Reaction

[highcoughdrop]

Homework Statement

An ice cube of mass 36 g at temperature -10 Celsius is placed in 360 g of water at 20 Celsius. Find thermal equilibrium temperature. $$\Delta$$H(fusion) = 6.007 kJ mol$$\wedge$$-1.

Molar heat capacity of ice = 38
water = 75 (Joules)/(K mol)

Assume no heat loss to the surroundings.

Homework Equations

$$\Delta$$ H = n(Cp) $$\Delta$$T

q = M (Cs) delta T

The Attempt at a Solution

I tried to find the thermal temperature first by using the temperature above, but I got different temperatures that were not even close to what they should be. THe thermal temperatures should be between -10 and 20, however they are going to be closer to the 20 because water mass is much more than mass of ice.

 

[vertciel]

Hello there,

You are missing a key equation:

mc∆T = -mc∆T,

where ∆T = T_f - T_i.

I encourage you to learn this equation and then retry the problem. If you need any more help, please write back!

 

[Borek]

mc∆T = -mc∆T,

where ∆T = T_f - T_i

First - it is a very particular case.

Second - it doesn't account for the ice melting.

highcoughdrop: heat gained = heat lost; can you list all partial heats thet wll be lost/gained before ysstem will get to the equilibrium?