(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Two different ideal gases are separated by a sliding barrier that can move vertically. The gas in the upper chamber 1 has n moles of material, whilst the gas in the lower chamber 2 has 3n moles of material. At T_{0}the weight of the barrier is such that the volumes of the two chambers are equal. What is the ratio of V_{2}/V_{1}at T_{1}.

2. Relevant equations

P = F/A

W = mg

PV = nRT

3. The attempt at a solution

Equilibrium at T_{0}: F_{2}= F_{1}+ W

where the F_{i}are the forces from the i gas on the barrier.

therefore W = F_{2}- F_{1}= A(P_{2}- P_{1})

[itex] \frac{3AnRT_{0}}{V_{2}} - \frac{AnRT_{0}}{V_{1}} = \frac{2AnRT_{0}}{V_{0}} [/itex], because [itex]V_{0} = V_{1}(T_{0}) = V_{2}(T_{0})[/itex]

further [itex] W = \frac{4AnRT_{0}}{V} [/itex], because [itex]V_{0} = \frac{V}{2}[/itex] where V is the total volume of the two chambers!

Now I want to check equilibrium forces at T_{1}but using F_{2}= F_{1}+ W for T_{1}and substituting for constant weight will not allow me to calculate the ratio V_{2}/V_{1}!

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# Homework Help: Thermodyn.: ideal gases in 2 two chambers separated by a sliding barrier

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